x^2+6x+12=3

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Solution for x^2+6x+12=3 equation: 



x^2+6x+12=3

We move all terms to the left:

x^2+6x+12-(3)=0

We add all the numbers together, and all the variables

x^2+6x+9=0

a = 1; b = 6; c = +9;
Δ = b2-4ac
Δ = 62-4·1·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-6}{2}=-3$

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